Optimal. Leaf size=199 \[ -\frac {b (2 b B c-A b d-2 a B d) x}{d^3}-\frac {2 (b c-a d) \left (a d^2 (A c-B d)-b \left (2 B c^3-A c^2 d-3 B c d^2+2 A d^3\right )\right ) \tan ^{-1}\left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{d^3 \left (c^2-d^2\right )^{3/2} f}-\frac {b^2 B \cos (e+f x)}{d^2 f}-\frac {(b c-a d)^2 (B c-A d) \cos (e+f x)}{d^2 \left (c^2-d^2\right ) f (c+d \sin (e+f x))} \]
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Rubi [A]
time = 0.40, antiderivative size = 199, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.171, Rules used = {3067, 3102,
2814, 2739, 632, 210} \begin {gather*} -\frac {2 (b c-a d) \left (a d^2 (A c-B d)-b \left (-A c^2 d+2 A d^3+2 B c^3-3 B c d^2\right )\right ) \text {ArcTan}\left (\frac {c \tan \left (\frac {1}{2} (e+f x)\right )+d}{\sqrt {c^2-d^2}}\right )}{d^3 f \left (c^2-d^2\right )^{3/2}}-\frac {(b c-a d)^2 (B c-A d) \cos (e+f x)}{d^2 f \left (c^2-d^2\right ) (c+d \sin (e+f x))}-\frac {b x (-2 a B d-A b d+2 b B c)}{d^3}-\frac {b^2 B \cos (e+f x)}{d^2 f} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 632
Rule 2739
Rule 2814
Rule 3067
Rule 3102
Rubi steps
\begin {align*} \int \frac {(a+b \sin (e+f x))^2 (A+B \sin (e+f x))}{(c+d \sin (e+f x))^2} \, dx &=-\frac {(b c-a d)^2 (B c-A d) \cos (e+f x)}{d^2 \left (c^2-d^2\right ) f (c+d \sin (e+f x))}+\frac {\int \frac {-d \left (B (b c-a d)^2-A d \left (a^2 c+b^2 c-2 a b d\right )\right )-b (b B c-A b d-2 a B d) \left (c^2-d^2\right ) \sin (e+f x)+b^2 B d \left (c^2-d^2\right ) \sin ^2(e+f x)}{c+d \sin (e+f x)} \, dx}{d^2 \left (c^2-d^2\right )}\\ &=-\frac {b^2 B \cos (e+f x)}{d^2 f}-\frac {(b c-a d)^2 (B c-A d) \cos (e+f x)}{d^2 \left (c^2-d^2\right ) f (c+d \sin (e+f x))}+\frac {\int \frac {-d^2 \left (B (b c-a d)^2-A d \left (a^2 c+b^2 c-2 a b d\right )\right )-b d (2 b B c-A b d-2 a B d) \left (c^2-d^2\right ) \sin (e+f x)}{c+d \sin (e+f x)} \, dx}{d^3 \left (c^2-d^2\right )}\\ &=-\frac {b (2 b B c-A b d-2 a B d) x}{d^3}-\frac {b^2 B \cos (e+f x)}{d^2 f}-\frac {(b c-a d)^2 (B c-A d) \cos (e+f x)}{d^2 \left (c^2-d^2\right ) f (c+d \sin (e+f x))}-\frac {\left ((b c-a d) \left (a d^2 (A c-B d)-b \left (2 B c^3-A c^2 d-3 B c d^2+2 A d^3\right )\right )\right ) \int \frac {1}{c+d \sin (e+f x)} \, dx}{d^3 \left (c^2-d^2\right )}\\ &=-\frac {b (2 b B c-A b d-2 a B d) x}{d^3}-\frac {b^2 B \cos (e+f x)}{d^2 f}-\frac {(b c-a d)^2 (B c-A d) \cos (e+f x)}{d^2 \left (c^2-d^2\right ) f (c+d \sin (e+f x))}-\frac {\left (2 (b c-a d) \left (a d^2 (A c-B d)-b \left (2 B c^3-A c^2 d-3 B c d^2+2 A d^3\right )\right )\right ) \text {Subst}\left (\int \frac {1}{c+2 d x+c x^2} \, dx,x,\tan \left (\frac {1}{2} (e+f x)\right )\right )}{d^3 \left (c^2-d^2\right ) f}\\ &=-\frac {b (2 b B c-A b d-2 a B d) x}{d^3}-\frac {b^2 B \cos (e+f x)}{d^2 f}-\frac {(b c-a d)^2 (B c-A d) \cos (e+f x)}{d^2 \left (c^2-d^2\right ) f (c+d \sin (e+f x))}+\frac {\left (4 (b c-a d) \left (a d^2 (A c-B d)-b \left (2 B c^3-A c^2 d-3 B c d^2+2 A d^3\right )\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (c^2-d^2\right )-x^2} \, dx,x,2 d+2 c \tan \left (\frac {1}{2} (e+f x)\right )\right )}{d^3 \left (c^2-d^2\right ) f}\\ &=-\frac {b (2 b B c-A b d-2 a B d) x}{d^3}-\frac {2 (b c-a d) \left (a d^2 (A c-B d)-b \left (2 B c^3-A c^2 d-3 B c d^2+2 A d^3\right )\right ) \tan ^{-1}\left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{d^3 \left (c^2-d^2\right )^{3/2} f}-\frac {b^2 B \cos (e+f x)}{d^2 f}-\frac {(b c-a d)^2 (B c-A d) \cos (e+f x)}{d^2 \left (c^2-d^2\right ) f (c+d \sin (e+f x))}\\ \end {align*}
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Mathematica [A]
time = 1.10, size = 188, normalized size = 0.94 \begin {gather*} \frac {b (-2 b B c+A b d+2 a B d) (e+f x)+\frac {2 (b c-a d) \left (a d^2 (-A c+B d)+b \left (2 B c^3-A c^2 d-3 B c d^2+2 A d^3\right )\right ) \tan ^{-1}\left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{\left (c^2-d^2\right )^{3/2}}-b^2 B d \cos (e+f x)+\frac {d (b c-a d)^2 (-B c+A d) \cos (e+f x)}{(c-d) (c+d) (c+d \sin (e+f x))}}{d^3 f} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.72, size = 374, normalized size = 1.88
method | result | size |
derivativedivides | \(\frac {\frac {\frac {2 \left (\frac {d^{2} \left (a^{2} A \,d^{3}-2 A a b c \,d^{2}+A \,b^{2} c^{2} d -B \,a^{2} c \,d^{2}+2 B a b \,c^{2} d -c^{3} B \,b^{2}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{\left (c^{2}-d^{2}\right ) c}+\frac {d \left (a^{2} A \,d^{3}-2 A a b c \,d^{2}+A \,b^{2} c^{2} d -B \,a^{2} c \,d^{2}+2 B a b \,c^{2} d -c^{3} B \,b^{2}\right )}{c^{2}-d^{2}}\right )}{c \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+2 d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+c}+\frac {2 \left (A \,a^{2} c \,d^{3}-2 A a b \,d^{4}-A \,b^{2} c^{3} d +2 A \,b^{2} c \,d^{3}-B \,a^{2} d^{4}-2 B a b \,c^{3} d +4 B a b c \,d^{3}+2 B \,b^{2} c^{4}-3 B \,b^{2} c^{2} d^{2}\right ) \arctan \left (\frac {2 c \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+2 d}{2 \sqrt {c^{2}-d^{2}}}\right )}{\left (c^{2}-d^{2}\right )^{\frac {3}{2}}}}{d^{3}}+\frac {2 b \left (-\frac {B b d}{1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )}+\left (A b d +2 B a d -2 B b c \right ) \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )\right )}{d^{3}}}{f}\) | \(374\) |
default | \(\frac {\frac {\frac {2 \left (\frac {d^{2} \left (a^{2} A \,d^{3}-2 A a b c \,d^{2}+A \,b^{2} c^{2} d -B \,a^{2} c \,d^{2}+2 B a b \,c^{2} d -c^{3} B \,b^{2}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{\left (c^{2}-d^{2}\right ) c}+\frac {d \left (a^{2} A \,d^{3}-2 A a b c \,d^{2}+A \,b^{2} c^{2} d -B \,a^{2} c \,d^{2}+2 B a b \,c^{2} d -c^{3} B \,b^{2}\right )}{c^{2}-d^{2}}\right )}{c \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+2 d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+c}+\frac {2 \left (A \,a^{2} c \,d^{3}-2 A a b \,d^{4}-A \,b^{2} c^{3} d +2 A \,b^{2} c \,d^{3}-B \,a^{2} d^{4}-2 B a b \,c^{3} d +4 B a b c \,d^{3}+2 B \,b^{2} c^{4}-3 B \,b^{2} c^{2} d^{2}\right ) \arctan \left (\frac {2 c \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+2 d}{2 \sqrt {c^{2}-d^{2}}}\right )}{\left (c^{2}-d^{2}\right )^{\frac {3}{2}}}}{d^{3}}+\frac {2 b \left (-\frac {B b d}{1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )}+\left (A b d +2 B a d -2 B b c \right ) \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )\right )}{d^{3}}}{f}\) | \(374\) |
risch | \(\text {Expression too large to display}\) | \(1721\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 618 vs.
\(2 (198) = 396\).
time = 0.53, size = 1327, normalized size = 6.67 \begin {gather*} \left [-\frac {2 \, {\left (2 \, B b^{2} c^{6} - 4 \, B b^{2} c^{4} d^{2} + 2 \, B b^{2} c^{2} d^{4} - {\left (2 \, B a b + A b^{2}\right )} c^{5} d + 2 \, {\left (2 \, B a b + A b^{2}\right )} c^{3} d^{3} - {\left (2 \, B a b + A b^{2}\right )} c d^{5}\right )} f x + {\left (2 \, B b^{2} c^{5} - 3 \, B b^{2} c^{3} d^{2} - {\left (2 \, B a b + A b^{2}\right )} c^{4} d + {\left (A a^{2} + 4 \, B a b + 2 \, A b^{2}\right )} c^{2} d^{3} - {\left (B a^{2} + 2 \, A a b\right )} c d^{4} + {\left (2 \, B b^{2} c^{4} d - 3 \, B b^{2} c^{2} d^{3} - {\left (2 \, B a b + A b^{2}\right )} c^{3} d^{2} + {\left (A a^{2} + 4 \, B a b + 2 \, A b^{2}\right )} c d^{4} - {\left (B a^{2} + 2 \, A a b\right )} d^{5}\right )} \sin \left (f x + e\right )\right )} \sqrt {-c^{2} + d^{2}} \log \left (\frac {{\left (2 \, c^{2} - d^{2}\right )} \cos \left (f x + e\right )^{2} - 2 \, c d \sin \left (f x + e\right ) - c^{2} - d^{2} + 2 \, {\left (c \cos \left (f x + e\right ) \sin \left (f x + e\right ) + d \cos \left (f x + e\right )\right )} \sqrt {-c^{2} + d^{2}}}{d^{2} \cos \left (f x + e\right )^{2} - 2 \, c d \sin \left (f x + e\right ) - c^{2} - d^{2}}\right ) + 2 \, {\left (2 \, B b^{2} c^{5} d + A a^{2} d^{6} - {\left (2 \, B a b + A b^{2}\right )} c^{4} d^{2} + {\left (B a^{2} + 2 \, A a b - 3 \, B b^{2}\right )} c^{3} d^{3} - {\left (A a^{2} - 2 \, B a b - A b^{2}\right )} c^{2} d^{4} - {\left (B a^{2} + 2 \, A a b - B b^{2}\right )} c d^{5}\right )} \cos \left (f x + e\right ) + 2 \, {\left ({\left (2 \, B b^{2} c^{5} d - 4 \, B b^{2} c^{3} d^{3} + 2 \, B b^{2} c d^{5} - {\left (2 \, B a b + A b^{2}\right )} c^{4} d^{2} + 2 \, {\left (2 \, B a b + A b^{2}\right )} c^{2} d^{4} - {\left (2 \, B a b + A b^{2}\right )} d^{6}\right )} f x + {\left (B b^{2} c^{4} d^{2} - 2 \, B b^{2} c^{2} d^{4} + B b^{2} d^{6}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{2 \, {\left ({\left (c^{4} d^{4} - 2 \, c^{2} d^{6} + d^{8}\right )} f \sin \left (f x + e\right ) + {\left (c^{5} d^{3} - 2 \, c^{3} d^{5} + c d^{7}\right )} f\right )}}, -\frac {{\left (2 \, B b^{2} c^{6} - 4 \, B b^{2} c^{4} d^{2} + 2 \, B b^{2} c^{2} d^{4} - {\left (2 \, B a b + A b^{2}\right )} c^{5} d + 2 \, {\left (2 \, B a b + A b^{2}\right )} c^{3} d^{3} - {\left (2 \, B a b + A b^{2}\right )} c d^{5}\right )} f x + {\left (2 \, B b^{2} c^{5} - 3 \, B b^{2} c^{3} d^{2} - {\left (2 \, B a b + A b^{2}\right )} c^{4} d + {\left (A a^{2} + 4 \, B a b + 2 \, A b^{2}\right )} c^{2} d^{3} - {\left (B a^{2} + 2 \, A a b\right )} c d^{4} + {\left (2 \, B b^{2} c^{4} d - 3 \, B b^{2} c^{2} d^{3} - {\left (2 \, B a b + A b^{2}\right )} c^{3} d^{2} + {\left (A a^{2} + 4 \, B a b + 2 \, A b^{2}\right )} c d^{4} - {\left (B a^{2} + 2 \, A a b\right )} d^{5}\right )} \sin \left (f x + e\right )\right )} \sqrt {c^{2} - d^{2}} \arctan \left (-\frac {c \sin \left (f x + e\right ) + d}{\sqrt {c^{2} - d^{2}} \cos \left (f x + e\right )}\right ) + {\left (2 \, B b^{2} c^{5} d + A a^{2} d^{6} - {\left (2 \, B a b + A b^{2}\right )} c^{4} d^{2} + {\left (B a^{2} + 2 \, A a b - 3 \, B b^{2}\right )} c^{3} d^{3} - {\left (A a^{2} - 2 \, B a b - A b^{2}\right )} c^{2} d^{4} - {\left (B a^{2} + 2 \, A a b - B b^{2}\right )} c d^{5}\right )} \cos \left (f x + e\right ) + {\left ({\left (2 \, B b^{2} c^{5} d - 4 \, B b^{2} c^{3} d^{3} + 2 \, B b^{2} c d^{5} - {\left (2 \, B a b + A b^{2}\right )} c^{4} d^{2} + 2 \, {\left (2 \, B a b + A b^{2}\right )} c^{2} d^{4} - {\left (2 \, B a b + A b^{2}\right )} d^{6}\right )} f x + {\left (B b^{2} c^{4} d^{2} - 2 \, B b^{2} c^{2} d^{4} + B b^{2} d^{6}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{{\left (c^{4} d^{4} - 2 \, c^{2} d^{6} + d^{8}\right )} f \sin \left (f x + e\right ) + {\left (c^{5} d^{3} - 2 \, c^{3} d^{5} + c d^{7}\right )} f}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 776 vs.
\(2 (198) = 396\).
time = 0.46, size = 776, normalized size = 3.90 \begin {gather*} \frac {\frac {2 \, {\left (2 \, B b^{2} c^{4} - 2 \, B a b c^{3} d - A b^{2} c^{3} d - 3 \, B b^{2} c^{2} d^{2} + A a^{2} c d^{3} + 4 \, B a b c d^{3} + 2 \, A b^{2} c d^{3} - B a^{2} d^{4} - 2 \, A a b d^{4}\right )} {\left (\pi \left \lfloor \frac {f x + e}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (c\right ) + \arctan \left (\frac {c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + d}{\sqrt {c^{2} - d^{2}}}\right )\right )}}{{\left (c^{2} d^{3} - d^{5}\right )} \sqrt {c^{2} - d^{2}}} - \frac {2 \, {\left (B b^{2} c^{3} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 2 \, B a b c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - A b^{2} c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + B a^{2} c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 2 \, A a b c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - A a^{2} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 2 \, B b^{2} c^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 2 \, B a b c^{3} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - A b^{2} c^{3} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + B a^{2} c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 2 \, A a b c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - B b^{2} c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - A a^{2} c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 3 \, B b^{2} c^{3} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 2 \, B a b c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - A b^{2} c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + B a^{2} c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 2 \, A a b c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 2 \, B b^{2} c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - A a^{2} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 2 \, B b^{2} c^{4} - 2 \, B a b c^{3} d - A b^{2} c^{3} d + B a^{2} c^{2} d^{2} + 2 \, A a b c^{2} d^{2} - B b^{2} c^{2} d^{2} - A a^{2} c d^{3}\right )}}{{\left (c^{3} d^{2} - c d^{4}\right )} {\left (c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{4} + 2 \, d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 2 \, c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 2 \, d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + c\right )}} - \frac {{\left (2 \, B b^{2} c - 2 \, B a b d - A b^{2} d\right )} {\left (f x + e\right )}}{d^{3}}}{f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 27.62, size = 2500, normalized size = 12.56 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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